Differences
This shows you the differences between two versions of the page.
| Both sides previous revisionPrevious revisionNext revision | Previous revision | ||
| articles:soot [2025/07/26 20:22] – [What does this mean?] rrandall | articles:soot [2025/07/26 21:48] (current) – [What does this mean?] rrandall | ||
|---|---|---|---|
| Line 19: | Line 19: | ||
| **Rule (a):** \\ | **Rule (a):** \\ | ||
| The Measuring and Test Equipment (M&TE) out-of-tolerance condition exceeds 25% of the product tolerance (the maximum acceptable level of deviation from a product’s specification, | The Measuring and Test Equipment (M&TE) out-of-tolerance condition exceeds 25% of the product tolerance (the maximum acceptable level of deviation from a product’s specification, | ||
| + | |||
| + | <wrap em>This SOOT criteria focuses on the Accuracy Ratio as it relates to the product... without consideration to the accuracy of the measuring device.</ | ||
| __Example: | __Example: | ||
| Line 49: | Line 51: | ||
| **Rule (b):** \\ | **Rule (b):** \\ | ||
| The Measuring and Test Equipment (M&TE) error is greater than twice the calibration tolerance when product tolerance isn't known. \\ | The Measuring and Test Equipment (M&TE) error is greater than twice the calibration tolerance when product tolerance isn't known. \\ | ||
| + | |||
| + | <wrap em>This SOOT criteria focuses on the Accuracy Ratio as it relates to the measuring device... without consideration to the tolerances associated with the product.</ | ||
| __Example: | __Example: | ||
| - | Keeping with the above example, suppose your measuring device has a calibration tolerance of ±0.5 mm (meaning the device could be off by ±0.5 mm). \\ | + | Keeping with the above example, suppose your measuring device has a calibration tolerance of ±0.5 mm (meaning the device could be off by ±0.5 mm). This provides a 4:1 Accuracy Ratio with the produce tolerance being measured.\\ |
| - | Twice the calibration tolerance = 2 × 0.5 mm = 1.0 mm \\ | + | Twice the calibration tolerance = 2 × 0.5 mm = ±1.0 mm \\ |
| __Calibration of Measuring Device__ \\ | __Calibration of Measuring Device__ \\ | ||
| - | Assume that the measuring device was calibrated at 100.0 mm and found to read 99.3 mm (0.7 mm low). | + | Assume that the measuring device was calibrated at 100.0 mm and found to read 98.9 mm (1.1 mm low). |
| - | + | ||
| - | This means the device understates its measurements by 0.7 mm (since 100.0 mm - 99.3 mm = 0.7 mm). | + | |
| - | + | ||
| - | Bias: -0.7 mm (the device' | + | |
| - | + | ||
| - | __Measurements__ \\ | + | |
| - | + | ||
| - | Since the measuring device has a tolerance of ±0.5 mm, in a worst possible scenario, even with a measuring device found in tolerance, the part could actually be read | + | |
| - | + | ||
| - | + | ||
| - | When taking a measurement, | + | |
| - | + | ||
| - | However, the " | + | |
| - | + | ||
| - | This means: 100.2 mm + 0.7 mm = 100.9 mm | + | |
| + | This means the measuring device error was found to be greater than twice the calibration tolerance. | ||
| + | Conclusion: \\ | ||
| + | This somewhat arbitrary approach toward defining a SOOT condition has little to do with determining the IMPACT of the Out-Of-Tolerance (OOT) condition. \\ | ||
| - | Conclusion: | + | If we know the product tolerance, and determine that it had been a 4:1 Accuracy Ration, then halving |
| - | 102.1 mm > 102 mm, so the part is out of tolerance | + | |
| - | This means that whatever reading your measuring device | + | <wrap em> |
| - | So if your device displays a measurement of 101.0 mm, it's true reading | + | In that case, an error of twice the calibration tolerance |
| - | Since the bias (1.1 mm) this is more than twice the calibration tolerance (± 1.0 mm) this is a SOOT condition. | ||
| ===== Why was this added to their requirements? | ===== Why was this added to their requirements? | ||

